Javascript tips

Merging multiple objects

You may have a need to merge two objects together and create a better informative object to work with. You can use the spread operator ...(yes, three dots!). Consider two objects, emp and job respectively,

let emp = {
 'id': 'E_01',
 'name': 'Jack',
 'age': 32,
 'addr': 'India'

let job = {
 'title': 'Software Dev',
  'location': 'Paris'

Merge them using the spread operator as,

 // spread operator
 let merged = {...emp, ...job};
 console.log('Spread merged', merged);

There is another way to perform this merge. Using Object.assign(). You can do it like,

 console.log('Object assign', Object.assign({}, emp, job));

Output: Note, both the spread operator and the Object.assign perform a shallow merge. In a shallow merge, the properties of the first object are overwritten with the same property values as the second object. For deep merge, please use something like, _merge of lodash.

Comma Operator

I was surprised when I realized, comma(,) is a separate operator and never gone noticed. I have been using it so much in code but, never realized its true existence. In JavaScript, the comma(,) operator is used for evaluating each of its operands from left to right and returns the value of the last operand.

let count = 1;
let ret = (count++, count);

In the above example, the value of the variable ret will be, 2. Similar way, the output of the following code will be logging the value 32 into the console.

let val = (12, 32);

Where do we use it? Any guesses? The most common usage of the comma(,) operator is to supply multiple parameters in a for loop.

for (var i = 0, j = 50; i <= 50; i++, j--)

Required Function Params

Expanding on the default parameter technique, we can mark a parameter as mandatory. First define a function to throw an error with an error message,

let isRequired = () => {
    throw new Error('This is a mandatory parameter.');

Then assign the function as the default value for the required parameters. Remember, the default values are ignored when a value is passed for a parameter at the invocation time. But, the default value is considered if the parameter value is undefined.

let greetings = (name=isRequired(), message='Hello,') => {
    return `${message} ${name}`;

In the above code, name will be undefined and that will try to set the default value for it which is the isRequired() function. It will throw an error as,

Function default params

In JavaScript, function arguments(or params) are like local variables to that function. You may or may not pass values for those while invoking the function. If you do not pass a value for a param, it will be undefined and may cause some unwanted side effects. There is a simple way to pass a default value to the function parameters while defining them. Here is an example where we are passing the default value Hello to the parameter message of the greetings function.

let greetings = (name, message='Hello,') => {
    return `${message} ${name}`;

console.log(greetings('Jack', 'Hola!'));


Generating random numbers or getting a random item from an array are very useful methods to keep handy. I have seen them appearing multiple times in many of my projects. Get a random item from an array,

let planets = ['Mercury ', 'Mars', 'Venus', 'Earth', 'Neptune', 'Uranus', 'Saturn', 'Jupiter'];
let randomPlanet = planets[Math.floor(Math.random() * planets.length)];
console.log('Random Planet', randomPlanet);

Generate a random number from a range by specifying the min and max values,

 let getRandom = (min, max) => {
     return Math.round(Math.random() * (max - min) + min);
 console.log('Get random', getRandom(0, 10));

The default value with OR

If you ever like to set a default value for a variable, you can do it using the OR(||) operator easily.

let person = {name: 'Jack'};
let age = person.age || 35; // sets the value 35 if age is undefined
console.log(`Age of ${} is ${age}`);

But wait, it has a problem. What if the person's age is 0(a just born baby, maybe). The age will be computed as 35 (0 || 35 = 35). This is unexpected behavior. Enter the nullish coalescing operator (??). It is a logical operator that returns its right-hand side operand when its left-hand side operand is null or undefined and otherwise returns its left-hand side operand. To rewrite the above code with the ?? operator,

let person = {name: 'Jack'};
let age = person.age ?? 35; // sets the value 0 if age 0, 35 in case of undefined and null
console.log(`Age of ${} is ${age}`);

Shorthand with AND

Let's consider a situation where we have a boolean value and a function.

let isPrime = true;
const startWatching = () => {
    console.log('Started Watching!');

This is too much code to check for the boolean condition and invoke the function,

if (isPrime) {

How about using the short-hand using the AND(&&) operator? Yes, avoid if statements altogether. Cool, right?

isPrime && startWatching();

Value as Number

Have you ever noticed, always returns a string type value even when the input box is of type number? Yes, see the example below. We have a simple text box of type number. It means it accepts only numbers as input. It has an event handler to handle the key-up events.

<input type='number' onkeyup="trackChange(event)" />

In the event handler method, we take out the value using But it returns a string type value. Now I will have an additional headache to parse it to an integer. What if the input box accepts floating numbers(like, 16.56)? parseFloat() then? Ah, all sorts of confusion and extra work!

function trackChange(event) {
   let value =;
   console.log(`is ${value} a number?`, Number.isInteger(value));

Use instead. It returns the value as number.

let valueAsNumber =;
console.log(`is ${value} a number?`, Number.isInteger(valueAsNumber));


There is a much cleaner way to know if a value is an integer. The Number API of JavaScript provides a method called, isInteger() to serve this purpose. It is very useful and better to be aware of.

let mynum = 123;
let mynumStr = "123";

console.log(`${mynum} is a number?`, Number.isInteger(mynum));
console.log(`${mynumStr} is a number?`, Number.isInteger(mynumStr));


Forget string concatenation, use template string(literal)

Concatenating strings together using the + operator to build a meaningful string is old school. Moreover, concatenating strings with dynamic values(or expressions) could lead to frustrations and bugs.

let name = 'Charlse';
let place = 'India';
let isPrime = bit => {
  return (bit === 'P' ? 'Prime' : 'Nom-Prime');

// string concatenation using + operator
let messageConcat = 'Mr. ' + name + ' is from ' + place + '. He is a' + ' ' + isPrime('P') + ' member.'

Template literals(or Template strings) allow embedding expressions. It has got unique syntax where the string has to be enclosed by the backtick (``). Template string can contain placeholders for dynamic values. These are marked by the dollar sign and curly braces (${expression}). Here is an example demonstrating it,

let name = 'Charlse';
let place = 'India';
let isPrime = bit => {
  return (bit === 'P' ? 'Prime' : 'Nom-Prime');

// using template string
let messageTemplateStr = `Mr. ${name} is from ${place}. He is a ${isPrime('P')} member.`